hans wurst schrieb....
	Zitat:
	
	
		| PS: "The plane´s left wing actually came in near the ground and the right wing was tilted up in the air."
 Augenzeuge Jack Singleton
 
 Rechter Flügel der eher nach oben zeigt - Würde mit dem Einschlagloch
 und der "stehengebliebenen" Säule zusammenpassen.
 | 
	
 Diese Zeugenaussage halt ich für unglaubwürdig. Er will also im
Bruchteil einer Sekunde das erkannt haben? Außerdem hätte dann
der linke Flügel die Kabelrollen treffen müßen, da das Flugzeug angeblich
in 2 m über dem Boden geflogen sein soll.
Radar Altitude Confirms True Altitude
[quote name='johndoeX' date='Feb 16 2007, 04:59 PM' post='7977407']
We have recently been able to decode the additional data 'slipped' into our 
package through the FOIA (Thanks UT!).
The main purpose of getting this data decoded was to confirm or 
contradict our initial altitude findings regarding True altitude as 
shown in the animation and original csv file which can be seen in
Chapter Two.
The last recordings of radar altitude shown in the newly decoded .fdr file is as follows.
 
In the spirit of keeping this simple, we will use the argument side of the 
analysis prior to us getting the decode of the raw file.
Many of you have read our analysis regarding the altitude being too 
high based on True Altitude. However, the argument side says that
there could be up to 2 seconds error and possible lag due to instrument error.
Quote as follows from a self-proclaimed anonymous internet FDR Expert.
However, A radar altimeter presents no lag. The 273 feet you see 
above is a hard number 
above the ground. 
Now we will disregard when it was recorded and use the argument 
side that there could be 'up to' 2 seconds missing (ie. the 273' was 
recorded 2 seconds prior to the pentagon wall).
Backing the data out from the pentagon wall 2 seconds based on 
speed, the aircraft is at this location...
(again using the govt loyalist argument of the south flight path)
 
The ground elevation at this point is ~60 feet above sea level. 
Add that to 273 and you get 333 feet above sea level. (this figure 
does not match True altitude at this point because we are using 
the govt loyalist hypothetical that 273 was recorded 'up to' 2 seconds 
out from the pentagon.. we are using their argument of the largest 
margin for error).
The elevation of the 'hole' in the pentagon is 33 (ground elevation
of pentagon, established) plus 12' (center of hole) = 45 feet above sea level.
When we subtract 333 from 45, we get a number of 288 feet
above the 'impact hole' at a spot 2 seconds away from impact.
Divide 288 by 2(seconds) and this aircraft would need a steady
linear descent rate of 8,640 feet per minute to impact the hole in 
the pentagon (remember, this is using the argument that 273 was 
recorded up to 2 seconds prior to impact). This is in direct conflict 
with the DoD video showing an object level across the lawn.
 
Now, lets look at the light poles.
We will again use the govt loyalist argument that the height of the poles 
was 66(ground elevation, although the USGS shows 43) + 40 feet for pole 
height (liberal figure) = 106 feet.
Based on forward speed, the light poles were ~1 second from impact 
(its more like 1.3 for poles one and two, but we're giving the govt loyalists 
every chance possible here).
So, that being the case, if we were using the 273 AGL altitude as
recorded by the radar altimeter 2 seconds from the pentagon wall,
that would make the 273 agl recorded 1 second prior to the poles. 
The top of pole height was 106 feet above sea level. The
"2 second recording" was 333 feet above sea level. Subtact the 
two and you get 227 feet this aircraft would have had to descend 
in order to hit the very top of pole 1 within
 one second(again, 
using liberal numbers for pole height... its actually more than 227).
To descend 227 feet in one second, this aircraft would need 
13,620 feet per minute dive to clip the poles. And then level 
off from that dive to be level with the pentagon lawn.
 
To level off from that dive, the aircraft would need to pull 
(227/32 (ft/sec, accel due to gravity) =7+1G's (earths gravity) = 
<span>8</span> 
total G's for 1 second sustained to be level with the lawn.
There is no indication anywhere in ther FDR file showing this 
aircraft pulling 8 G's sustained during the last second, Matter of fact, it shows less 
than 1 G.. Not to mention, aircraft structural limitation would not let it get that high.
IE. The wings would rip off and/or High speed buffet/stall.
Conclusion:
Using the govt loyalist own argument of 'up to' 2 seconds of error, 
we can see this aircraft was too high to hit the poles and the pentagon.
However, using the actual data that was recorded 1 second 
prior to the pentagon wall as provided directly from the NTSB 
(and not making excuses like there may be 'up to 2 seconds missing'),
it is further in conflict with the govt story.
Cheers!
Rob
"If his true altitude is accurate, he may be on to something" - 
Anonymous Self-Proclaimed FDR Expert and Govt Loyalist.
(if you want to repost this whole article, pictures and all, hit the quote 
button and copy and past the quote to your new post in 
another forum. Spread it everywhere if you like).
[/quote]
Die Belastungsgrenze einer 757 liegt bei 3 G für wenige
Sekunden. Bei 8 G reißen die Tragflächen ab.
Und die Flughöhe wird in der Simulation korrekt
dargestellt.